In a circuit with capacitors connected in series, how does the total capacitance compare to the individual capacitors?

Prepare for the Michelin ECT Exam. Study with comprehensive flashcards and multiple choice questions, each with detailed hints and explanations. Get ready to excel in your exam!

Multiple Choice

In a circuit with capacitors connected in series, how does the total capacitance compare to the individual capacitors?

Explanation:
When capacitors are in series, the same amount of charge must be stored on each one, so the charge Q is the same for every capacitor. The total voltage across the chain is the sum of the individual voltages, with each voltage given by Vi = Q / Ci. Therefore V_total = Q × sum(1/Ci). The equivalent capacitance is C_eq = Q / V_total = 1 / sum(1/Ci). Since the sum of reciprocals is larger than any single reciprocal, C_eq is smaller than any individual capacitance. Adding more capacitors in series thus lowers the total capacitance (for two identical caps, it becomes C/2). This is in contrast to capacitors in parallel, where the capacitances add and the total increases.

When capacitors are in series, the same amount of charge must be stored on each one, so the charge Q is the same for every capacitor. The total voltage across the chain is the sum of the individual voltages, with each voltage given by Vi = Q / Ci. Therefore V_total = Q × sum(1/Ci). The equivalent capacitance is C_eq = Q / V_total = 1 / sum(1/Ci). Since the sum of reciprocals is larger than any single reciprocal, C_eq is smaller than any individual capacitance. Adding more capacitors in series thus lowers the total capacitance (for two identical caps, it becomes C/2). This is in contrast to capacitors in parallel, where the capacitances add and the total increases.

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy